If you need any clarification, have doubt or have better solution… Don’t forget to leave a comment.

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About the Author

Aloha, I'm Amit Ghosh, a web entrepreneur and avid blogger. Bitten by entrepreneurial bug, I got kicked out from college and ended up being millionaire and running a digital media company named Aeron7 headquartered at Lithuania.

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5 Comments
 
  1. Saptak Bhattacharya • April 4, 2016 at 1:51 pm •Reply

    Problem 9:-xi=1 implies that (n-1)=1 or n=2,but it is mentioned that n>=3…I think there will be no solution….if you consider none of the values to be equal….you get x1xn=x2xn-1=…..=1….plugging in,we have x1=xn,x2=xn-1,which are contradictions..hence all values must be equal..which again results in n=2..another contradiction…thus,no solution……I might be wrong,you have the license to laugh at me…..

  2. Aditya Narayan Sharma • November 27, 2016 at 12:13 am •Reply

    Hello Amit sir, I am aditya narayan sharma (a high school student) . I guess in Q7 the answer should be 4900 as it should be n(n+1)(2n+1)/6 , a tiny hand typo rather.

    • Amit Ghosh • November 27, 2016 at 12:18 am •Reply

      I am not sir brother :) Was a student like you once. You’re correct! But I’m too lazy to fix this now haha.

  3. aditya • April 12, 2017 at 3:10 am •Reply

    sir I think in qs n. 7 the limits shud be from 0 to 23 as (i,j)<=24 so smallst square can be of unit 1 . we can choose 23 such lengths . i may be wrong too so kindly clear this doubt

  4. aditya • April 12, 2017 at 3:39 am •Reply

    sorry i actually intended to write from 1 to 23

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